2 A table of integrals

We could use a table of derivatives to find integrals, but the more common ones are usually found in a ‘Table of Integrals’ such as that shown below. You could check the entries in this table using your knowledge of differentiation. Try this for yourself.

Table 1: Integrals of Common Functions

function indefinite integral
f ( x ) ∫ f ( x ) d x
constant, k k x + c
   
x 1 2 x 2 + c
   
x 2 1 3 x 3 + c
   
x n x n + 1 n + 1 + c , n ≠ − 1
   
x − 1 (or   1 x ) ln x + c
   
cos x sin x + c
   
sin x − cos x + c
   
cos k x 1 k sin k x + c
   
sin k x − 1 k cos k x + c
   
tan k x 1 k ln sec k x +c
   
e x e x + c
   
e − x − e − x + c
   
e k x 1 k e k x + c

When dealing with the trigonometric functions the variable x must always be measured in radians and not degrees. Note that the fourth entry in the Table, for x n , is valid for any value of n , positive or negative, whole number or fractional, except n = − 1 . When n = − 1 use the fifth entry in the Table.

Example 1

Use Table 1 to find the indefinite integral of x 7 : that is, find ∫ x 7 d x

Solution

From Table 1 note that ∫ x n d x = x n + 1 n + 1 + c . In words, this states that to integrate a power of x , increase the power by 1, and then divide the result by the new power. With n = 7 we find

∫ x 7 d x = 1 8 x 8 + c

Example 2

Find the indefinite integral of cos 5 x : that is, find ∫ cos 5 x d x

Solution

From Table 1 note that ∫ cos k x d x = sin k x k + c

With k = 5 we find ∫ cos 5 x d x = 1 5 sin 5 x + c

In Table 1 the independent variable is always given as x . However, with a little imagination you will be able to use it when other independent variables are involved.

Example 3

Find ∫ cos 5 t d t

Solution

We integrated cos 5 x in the previous example. Now the independent variable is t , so simply use Table 1 and replace every x with a t . With k = 5 we find

∫ cos 5 t d t = 1 5 sin 5 t + c

It follows immediately that, for example,

∫ cos 5 ω d ω = 1 5 sin 5 ω + c , ∫ cos 5 u d u = 1 5 sin 5 u + c and so on.

Example 4

Find the indefinite integral of 1 x : that is, find ∫ 1 x d x

Solution

This integral deserves special mention. You may be tempted to try to write the integrand as x − 1 and use the fourth row of Table 1. However, the formula ∫ x n d x = x n + 1 n + 1 + c is not valid when n = − 1 as Table 1 makes clear. This is because we can never divide by zero. Look to the fifth entry of Table 1 and you will see ∫ x − 1 d x = ln x + c .

Example 5

Find ∫ 12 d x and ∫ 12 d t

Solution

In this Example we are integrating a constant, 12. Using Table 1 we find

∫ 12 d x = 12 x + c Similarly ∫ 12 d t = 12 t + c .

Task!

Find ∫ t 4 d t

∫ t 4 d t = 1 5 t 5 + c .

Task!

Find ∫ 1 x 5 d x using the laws of indices to write the integrand as x − 5 and then use Table 1:

− 1 4 x − 4 + c = − 1 4 x 4 + c .

Task!

Find ∫ e − 2 x d x using the entry in Table 1 for integrating e k x :

With k = − 2 , we have ∫ e − 2 x d x = − 1 2 e − 2 x + c .

Exercises
  1. Integrate each of the following functions with respect to x :
    1. x 9 ,
    2. x 1 ∕ 2 ,
    3. x − 3 ,
    4. 1 ∕ x 4 ,
    5. 4,
    6. x ,
    7. e 4 x
  2. Find
    1. ∫ t 2 d t ,
    2. ∫ 6 d t ,
    3. ∫ sin 3 t d t ,
    4. ∫ e 7 t d t .
    1. 1 10 x 10 + c ,
    2. 2 3 x 3 ∕ 2 + c ,
    3. − 1 2 x − 2 + c ,
    4. − 1 3 x − 3 + c ,
    5. 4 x + c ,
    6. same as (b),
    7. 1 4 e 4 x + c
    1. 1 3 t 3 + c ,
    2. 6 t + c ,
    3. − 1 3 cos 3 t + c ,
    4. 1 7 e 7 t + c