2 Engineering Example 2

2.1 Sonic boom

Introduction

Impulsive signals are described by their peak amplitudes and their duration. Another quantity of interest is the total energy of the impulse. The effect of a blast wave from an explosion on structures, for example, is related to its total energy. This Example looks at the calculation of the energy on a sonic boom. Sonic booms are caused when an aircraft travels faster than the speed of sound in air. An idealized sonic-boom pressure waveform is shown in Figure 6 where the instantaneous sound pressure p ( t ) is plotted versus time t . This wave type is often called an N-wave because it resembles the shape of the letter N. The energy in a sound wave is proportional to the square of the sound pressure.

Figure 6 :

{ An idealized sonic-boom pressure waveform}

Problem in words

Calculate the energy in an ideal N-wave sonic boom in terms of its peak pressure, its duration and the density and sound speed in air.

Mathematical statement of problem

Represent the positive peak pressure by P 0 and the duration by T . The total acoustic energy E carried across unit area normal to the sonic-boom wave front during time T is defined by

E = < p ( t ) 2 > T ρ c (1)

where ρ is the air density, c the speed of sound and the time average of [ p ( t ) ] 2 is

< p ( t ) 2 > = 1 T 0 T p ( t ) 2 d t (2)

  1. Find an appropriate expression for p ( t ) .
  2. Hence show that E can be expressed in terms of P 0 , T , ρ and c as    E = T P 0 2 3 ρ c .

Mathematical analysis

  1. The interval of integration needed to compute (2) is [ 0 , T ] . Therefore it is necessary to find an expression for p ( t ) only in this interval. Figure 6 shows that, in this interval, the dependence of the sound pressure p on the variable t is linear, i.e. p ( t ) = a t + b .

    From Figure 6 also p ( 0 ) = P 0 and p ( T ) = P 0 . The constants a and b are determined from these conditions.

    At t = 0 , a × 0 + b = P 0 implies that b = P 0 .

    At t = T , a × T + b = P 0 implies that a = 2 P 0 T .

    Consequently, the sound pressure in the interval [ 0 , T ] may be written    p ( t ) = 2 P 0 T t + P 0 .

  2. This expression for p ( t ) may be used to compute the integral (2) 1 T 0 T p ( t ) 2 d t = 1 T 0 T 2 P 0 T t + P 0 2 d t = 1 T 0 T 4 P 0 2 T 2 t 2 4 P 0 2 T t + P 0 2 d t = 1 T 4 P 0 2 3 T 2 t 3 2 P 0 2 T t 2 + P 0 2 t 0 T = P 0 2 T 4 3 T 2 T 3 2 T T 2 + T 0 = P 0 2 3.

    Hence, from Equation (1), the total acoustic energy E carried across unit area normal to the sonic-boom wave front during time T is E = T P 0 2 3 ρ c .

Interpretation

The energy in an N-wave is given by a third of the sound intensity corresponding to the peak pressure multiplied by the duration.

Exercises
  1. Calculate the mean value of the given functions across the specified interval.
    1. f ( t ) = 1 + t across [ 0 , 2 ]
    2. f ( x ) = 2 x 1 across [ 1 , 1 ]
    3. f ( t ) = t 2 across [ 0 , 1 ]
    4. f ( t ) = t 2 across [ 0 , 2 ]
    5. f ( z ) = z 2 + z across [ 1 , 3 ]
  2. Calculate the mean value of the given functions over the specified interval.
    1. f ( x ) = x 3 across [ 1 , 3 ]
    2. f ( x ) = 1 x across [ 1 , 2 ]
    3. f ( t ) = t across [ 0 , 2 ]
    4. f ( z ) = z 3 1 across [ 1 , 1 ]
  3. Calculate the mean value of the following:
    1. f ( t ) = sin t across 0 , π 2
    2. f ( t ) = sin t across 0 , π
    3. f ( t ) = sin ω t across [ 0 , π ]
    4. f ( t ) = cos t across 0 , π 2
    5. f ( t ) = cos t across 0 , π
    6. f ( t ) = cos ω t across [ 0 , π ]
    7. f ( t ) = sin ω t + cos ω t across [ 0 , 1 ]
  4. Calculate the mean value of the following functions:
    1. f ( t ) = t + 1 across [ 0 , 3 ]
    2. f ( t ) = e t across [ 1 , 1 ]
    3. f ( t ) = 1 + e t across [ 1 , 1 ]
    1. 2
    2. 1
    3. 1 3
    4. 4 3
    5. 19 3
    1. 10
    2. 0.6931
    3. 0.9428
    4. 1
    1. 2 π
    2. 2 π
    3. 1 π ω [ 1 cos ( π ω ) ]
    4. 2 π
    5. 0
    6. sin ( π ω ) π ω
    7. 1 + sin ω cos ω ω
    1. 14 9
    2. 1.1752
    3. 2.1752