3 Exact equations

Consider the differential equation

d y d x = 3 x 2

By direct integration we find that the general solution of this equation is

y = x 3 + C

where C is, as usual, an arbitrary constant of integration.

Next, consider the differential equation

d d x ( y x ) = 3 x 2 .

Again, by direct integration we find that the general solution is

y x = x 3 + C .

We now divide this equation by x to obtain

y = x 2 + C x .

The differential equation d d x ( y x ) = 3 x 2 is called an exact equation . It can effectively be solved by integrating both sides.

Task!

Solve the equations

  1. d y d x = 5 x 4
  2.   d d x ( x 3 y ) = 5 x 4
  1. y = x 5 + C
  2. x 3 y = x 5 + C so that y = x 2 + C x 3 .

If we consider examples of this kind in a more general setting we obtain the following Key Point:

Key Point 2

The solution of the equation

d d x ( f ( x ) y ) = g ( x )
is
f ( x ) y = g ( x ) d x or y = 1 f ( x ) g ( x ) d x