7 Engineering Example 1

7.1 Communication network

Problem in words

Figure 3 represents a communication network. Vertices a , b , f and g represent offices. Vertices c , d and e represent switching centres. The numbers marked along the edges represent the number of connections between any two vertices. Calculate the number of routes from a and b to f and g

Figure 3 :

A diagram representing a communication network with offices labeled a, b, f, and g, and switching centers labeled c, d, and e, with numbered connections between them.

Long description

Mathematical statement of the problem

The number of routes from a to f can be calculated by taking the number via c plus the number via d plus the number via e . In each case this is given by multiplying the number of connections along the edges connecting a to c , c to f etc. This gives the result:

Number of routes from a to f = 3 × 2 + 4 × 6 + 1 × 1 = 31.

The nature of matrix multiplication means that the number of routes is obtained by multiplying the matrix representing the number of connections from a b to c d e by the matrix representing the number of connections from c d e to f g .

Mathematical analysis

The matrix representing the number of routes from a b to c d e is:

A matrix with three rows and three columns containing the values c, d, e, a, 3, 4, 1, b, 2, 1, and 3. Long description

The matrix representing the number of routes from c d e to f g is:

A table or sequence of variables and numbers is shown, listing values for f, c, d, and e. Long description

The product of these two matrices gives the total number of routes.

3 4 1 2 1 3 2 1 6 3 1 2 = 3 × 2 + 4 × 6 + 1 × 1 3 × 1 + 4 × 3 + 1 × 2 2 × 2 + 1 × 6 + 3 × 1 2 × 1 + 1 × 3 + 3 × 2 = 31 17 13 11

Interpretation

We can interpret the resulting (product) matrix by labelling the columns and rows.

A matrix showing multiplication between three vectors or matrices: − − − 
 f \text{ } g \begin{pmatrix} a & 31 & 17 \ b & 13 & 11 \text{ \textendash \textendash \textendash} \text{ \textendash \textendash} \text{ \textendash} \text{ } \text{ \textendash} \text{ \textendash} \text{ \textendash} \end{pmatrix} Long description

Hence there are 31 routes from a to f , 17 from a to g , 13 from b to f and 11 from b to g .

Exercises
  1. If A = 1 2 3 4 B = 5 6 7 8 C = 0 1 2 3 find
    1. A B ,
    2. A C ,
    3. ( A + B ) C ,
    4. A C + B C (e)   2 A 3 C
  2. If a rotation through an angle θ is represented by the matrix A = cos θ sin θ sin θ cos θ and a second rotation through an angle ϕ is represented by the matrix B = cos ϕ sin ϕ sin ϕ cos ϕ show that both A B and B A represent a rotation through an angle θ + ϕ .
  3. If A = 1 2 3 1 1 1 2 2 2 , B = 2 4 1 2 5 6 , C = 2 1 1 2 , find A B and B C .
  4. If A = 1 2 1 0 1 2 , B = 1 2 3 5 0 0 1 2 1 , C = 0 1 2 ,

    verify A ( B C ) = ( A B ) C .

  5. If A = 2 3 1 0 1 2 4 5 6 then show that A A T is symmetric.
  6. If A = 11 0 2 1 B = 0 1 2 1 1 3 verify that ( A B ) T = 0 1 11 3 22 7 = B T A T
    1. A B = 19 22 43 50
    2.   A C = 4 7 8 15
    3.   ( A + B ) C = 16 30 24 46
    4. A C + B C = 16 30 24 46
    5.   2 7 0 17
  1. A B = cos θ cos ϕ sin θ sin ϕ cos θ sin ϕ + sin θ cos ϕ sin θ cos ϕ cos θ sin ϕ sin θ sin ϕ + cos θ cos ϕ

    = cos ( θ + ϕ ) sin ( θ + ϕ ) sin ( θ + ϕ ) cos ( θ + ϕ )

    which clearly represents a rotation through angle θ + ϕ . B A gives the same result.

  2. A B = 15 26 6 12 12 24 ,    B C = 8 10 0 3 16 17
  3. A ( B C ) = ( A B ) C = 8 8