5 Engineering Example 4

5.1 Velocity of a rocket

The upward velocity of a rocket, measured at 3 different times, is shown in the following table

Time, t Velocity, v
(seconds) (metres/second)
5 106.8
8 177.2
12 279.2

The velocity over the time interval 5 t 12 is approximated by a quadratic expression as

v ( t ) = a 1 t 2 + a 2 t + a 3

Find the values of a 1 , a 2 and a 3 .

Solution

Substituting the values from the table into the quadratic equation for v ( t ) gives:

106.8 = 25 a 1 + 5 a 2 + a 3
177.2 = 64 a 1 + 8 a 2 + a 3
279.2 = 144 a 1 + 12 a 2 + a 3
or 25 5 1 64 8 1 144 12 1 a 1 a 2 a 3 = 106.8 177.2 279.2

Applying one of the methods from this Workbook gives the solution as

a 1 = 0.2905 a 2 = 19.6905 a 3 = 1.0857 to 4 d.p.

As the original values were all experimental observations then the values of the unknowns are all approximations . The relation v ( t ) = 0.2905 t 2 + 19.6905 t + 1.0857 can now be used to predict the approximate position of the rocket for any time within the interval 5 t 12 .

Exercises

Solve the following using Gauss elimination:

1.

2 x 1 + x 2 x 3 = 0 x 1 + x 3 = 4 x 1 + x 2 + x 3 = 0

2.

x 1 x 2 + x 3 = 1 x 1 + x 3 = 1 x 1 + x 2 x 3 = 0

3.

x 1 + x 2 + x 3 = 2 2 x 1 + 3 x 2 + 4 x 3 = 3 x 1 2 x 2 x 3 = 1

4.

x 1 2 x 2 3 x 3 = 1 3 x 1 + x 2 + x 3 = 4 11 x 1 x 2 3 x 3 = 10

You may need to think carefully about this system.

  1. x 1 = 8 3 , x 2 = 4 , x 3 = 4 3
  2. x 1 = 1 2 , x 2 = 1 , x 3 = 3 2
  3. x 1 = 2 , x 2 = 1 , x 3 = 1
  4. infinite number of solutions: x 1 = t , x 2 = 11 10 t , x 3 = 7 t 7