4 The vector equation of a plane

Consider the plane shown in Figure 49.

Figure 49

No alt text was set. Please request alt text from the person who provided you with this resource.

Suppose that A is a fixed point in the plane and has position vector a ̲ . Suppose that P is any other arbitrary point in the plane with position vector r ̲ . Clearly the vector A P lies in the plane.

Task!

Referring to Figure 49, find the vector A P in terms of a ̲ and r ̲ .

r ̲ a ̲

Also shown in Figure 49 is a vector which is perpendicular to the plane and denoted by n ̲ .

Task!

What relationship exists between n ̲ and the vector A P ?

Hint: think about the scalar product:

Because A P and n ̲ are perpendicular their scalar product must equal zero, that is

( r ̲ a ̲ ) . n ̲ = 0 so that r ̲ . n ̲ = a ̲ . n ̲

The answer to the above Task, r ̲ . n ̲ = a ̲ . n ̲ , is the equation of a plane , written in vector form, passing through A and perpendicular to n ̲ .

Key Point 27

A plane perpendicular to the vector n ̲ and passing through the point with position vector a ̲ , has equation

r ̲ . n ̲ = a ̲ . n ̲

In this formula it does not matter whether or not n ̲ is a unit vector.

If n ̂ ̲ is a unit vector then a ̲ . n ̂ ̲ represents the perpendicular distance from the origin to the plane which we usually denote by d (for details of this see Section 9.3). Hence we can write

r ̲ . n ̂ ̲ = d

This is the equation of a plane , written in vector form, with unit normal n ̂ ̲ and which is a perpendicular distance d from O .

Key Point 28

A plane with unit normal n ̂ ̲ , which is a perpendicular distance d from O is given by

r ̲ . n ̂ ̲ = d
Example 23
  1. Find the vector equation of the plane which passes through the point with

    position vector   3 i ̲ + 2 j ̲ + 5 k ̲ and which is perpendicular to i ̲ + k ̲ .

  2. Find the Cartesian equation of this plane.
Solution
  1. Using the previous results we can write down the equation

    r ̲ . ( i ̲ + k ̲ ) = ( 3 i ̲ + 2 j ̲ + 5 k ̲ ) . ( i ̲ + k ̲ ) = 3 + 5 = 8

  2. Writing r ̲ as x i ̲ + y j ̲ + z k ̲ we have the Cartesian form:

    ( x i ̲ + y j ̲ + z k ̲ ) . ( i ̲ + k ̲ ) = 8

    so that

    x + z = 8

Task!
  1. Find the vector equation of the plane through ( 7 , 3 , 5 ) for which

    n ̲ = ( 1 , 1 , 1 ) is a vector normal to the plane.

  2. What is the distance of the plane from O ?
  1. Using the formula r ̲ n ̲ = a ̲ n ̲ the equation of the plane is

    r ̲ 1 1 1 = 7 3 5 1 1 1 = 7 × 1 + 3 × 1 5 × 1 = 5

  2. The distance from the origin is a ̲ . n ̂ ̲ = 7 3 5 1 3 1 1 1 = 5 3
Exercises
  1. Find the equation of a plane which is normal to 8 i ̲ + 9 j ̲ + k ̲ and which is a distance 1 from the origin. Give both vector and Cartesian forms.
  2. Find the equation of a plane which passes through ( 8 , 1 , 0 ) and which is normal to the vector i ̲ + 2 j ̲ 3 k ̲ .
  3. What is the distance of the plane r ̲ . 3 2 1 = 5 from the origin?
  1. r ̲ 1 146 8 9 1 = 1 ; 8 x + 9 y + z = 146 .
  2. r ̲ 1 2 3 = 8 1 0 1 2 3 , that is r ̲ 1 2 3 = 10 .
  3. 5 14