4 The vector equation of a plane
Consider the plane shown in Figure 49.
Figure 49
Suppose that is a fixed point in the plane and has position vector . Suppose that is any other arbitrary point in the plane with position vector . Clearly the vector lies in the plane.
Task!
Referring to Figure 49, find the vector in terms of and .
Also shown in Figure 49 is a vector which is perpendicular to the plane and denoted by .
Task!
What relationship exists between and the vector ?
Hint: think about the scalar product:
Because and are perpendicular their scalar product must equal zero, that is
so that
The answer to the above Task, is the equation of a plane , written in vector form, passing through and perpendicular to .
Key Point 27
A plane perpendicular to the vector and passing through the point with position vector , has equation
In this formula it does not matter whether or not is a unit vector.
If is a unit vector then represents the perpendicular distance from the origin to the plane which we usually denote by (for details of this see Section 9.3). Hence we can write
This is the equation of a plane , written in vector form, with unit normal and which is a perpendicular distance from .
Example 23
-
Find the vector equation of the plane which passes through the point with
position vector and which is perpendicular to .
- Find the Cartesian equation of this plane.
Solution
-
Using the previous results we can write down the equation
-
Writing
as
we have the Cartesian form:
so that
Task!
-
Find the vector equation of the plane through
for which
is a vector normal to the plane.
- What is the distance of the plane from ?
-
Using the formula
the equation of the plane is
- The distance from the origin is
Exercises
- Find the equation of a plane which is normal to and which is a distance 1 from the origin. Give both vector and Cartesian forms.
- Find the equation of a plane which passes through and which is normal to the vector .
- What is the distance of the plane from the origin?
- ; .
- , that is .