1 Trigonometric functions for any size angle

1.1 The radian

First we introduce an alternative to measuring angles in degrees. Look at the circle shown in Figure 19(a). It has radius r and we have shown an arc A B of length (measured in the same units as r .) As you can see the arc subtends an angle θ at the centre O of the circle.

Figure 19

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The angle θ in radians is defined as

θ = length of arc A B radius = r

So, for example, if r = 10 cm, = 20 cm, the angle θ would be 20 10 = 2 radians.

The relation between the value of an angle in radians and its value in degrees is readily obtained as follows. Referring to Figure 19(b) imagine that the arc A B extends to cover half the complete perimeter of the circle. The arc length is now π r (half the circumference of the circle) so the angle θ subtended by A B is now

θ = π r r = π radians

But clearly this angle is 18 0 . Thus π radians is the same as 18 0 .

Note conversely that since π radians = 18 0 then 1 radian = 180 π degrees (about 57 . 3 ).

Key Point 6

18 0 = π radians

36 0 = 2 π radians 1 radian = 180 π degrees ( 57 . 3 )

1 = π 180 radians

x = π x 180 radians y radians = 180 y π degrees

Task!

Write down the values in radians of 3 0 , 4 5 , 9 0 , 13 5 . (Leave your answers as multiples of π .)

3 0 = π × 30 180 = π 6 radians 4 5 = π 4 radians 9 0 = π 2 radians 13 5 = 3 π 4 radians

Task!

Write in degrees the following angles given in radians

π 10 , π 5 , 7 π 10 , 23 π 12

π 10 rad = 180 π × π 10 = 1 8 π 5 rad = 180 π × π 5 = 3 6 7 π 10 rad = 180 π × 7 π 10 = 12 6

23 π 12 rad = 180 π × 23 π 12 = 34 5

Task!

Put your calculator into radian mode (using the DRG button if necessary) for this Task: Verify these facts by first converting the angles to radians:

sin 3 0 = 1 2 cos 4 5 = 1 2 tan 6 0 = 3 (Use the π button to obtain π .)

sin 3 0 = sin π 6 = 0.5 , cos 4 5 = cos π 4 = 0.7071 = 1 2 ,

tan 6 0 = tan π 3 = 1.7320 = 3